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Thread: CS607 Assignment No 3 Solution

  1. #1
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    Music CS607 Assignment No 3 Solution

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  2. #2
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    you have to upload here.

  3. #3
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    Aoa
    i need solution of cs607 please upload it today.with regard

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    you posted it in wrong forum

  5. #5
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    Where is the Solution ... tonight is the list night???

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    no body haven't discuss solution with us. so how we can provide it.

  7. #7
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    Idea Solution :

    (v) (p → q)∧(p∨(q∧r)); (p∨q)∧(p∧(q∧r)); (p∨q)∧(p∧(q∨r));
    (p ∨ q) ∧ ((p ∧ q) ∨ (p ∧ r)); ((p ∨ q) ∧ (p ∧ q)) ∨ ((p ∨ q) ∧ (p ∧ r));
    ((p ∧ (p ∧ q)) ∨ (q ∧ (p ∧ q))) ∨ ((p ∧ (p ∧ r)) ∨ (q ∧ (p ∧ r)));
    (p∧q)∨(p∧q)∨(p∧r)∨(q ∧p∧r); (p∧q)∨(p∧r)∨(q ∧p∧r).
    So a disjunctive normal form is (p ∧ q) ∨ (p ∧ r) ∨ (q ∧ p ∧ r).
    We’ll directly find a conjunctive normal form from the original term:
    (p → q) ∧ (p ∨ (q ∧ r)); (p ∨ q) ∧ p ∧ (q ∧ r); (p ∨ q) ∧ p ∧ (q ∨ r),
    which is already a conjunctive normal form.

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