Assignment No.4 (Course STA301) Fall 2010 (Total Marks 30)

[harib raza]

faida to tab hota na jab ap time per solution upload kerty so is liay plz ab sta301 ka solution time per upload ker dein ta k hum log faida utha sakain
thanks

[ihsan]

Assignment # 04

STA 301 (Statistics and probability)



Question # 01

a)

Answer:

To give our Sampling distribution a state of normalization .In other words, As the sample size approaches infinity our sampling distribution of mean of X approaches normality Due to Central Limit Theorem, the normal distribution has found a central place in statistical inference



b)

“An estimate is a numerical value of the unknown parameter obtained by applying a rule or formula called an “estimator to the sample” taken from a population for instance, if X1, X2, X3…….Xn is a random sample of size n from a population with mean µ then,

i

X = 1/n ∑ Xi is called its estimator

n =1

Unknown parameter could be mean, median, mode, proportion or standard deviation In general, it is denoted by θ and its estimator is denoted by T



c) For any population parameter θ and its estimator T, the quantity

E (T) – θ is known as amount of bias

If this quantity is equal to zero then we say that our estimator is unbiased since unbiased ness is a desirable quality so we can regard our estimator as good one



d) The expression for confidence interval is given by



X + Z ά/2 σ/√n

For example in case of mean

There are two situations to achieve precision

1) Increase the level of significance or

2) Making the “n” small

By fulfilling one of these conditions the other becomes less précised so we need to strike a compromise between how low a level of confidence we can achieve and how wide an interval we can tolerate



e) 27.5 < < 43.8

Means that it is estimated that population mean lies somewhere between 27.5 and 43.8 and this statement is made on the basis of 85% confidence



Question # 02

a)

b) e = 0.05

q = 1 – p = 0.84

p = 0.16

Z 0.025 = 1.96

Formula for determining value of sample size in case of population proportion

n = [Z ά/2] pq

e

Putting values

n = [1.96 / 0.05] ^ 2 x (0.16) (0.84)

n = 206.52

n = 207

[harib raza]

xprt plz upload the complete solution.
today is last date.

[Zeshan Awan]

Xpert G plz upload the sta301 solution

[harib raza]

xprt gee kia ap tak hamari iltija nahi pohanch rahi
plz upload the solution file

[ihsan]

yaar koi tu upload kar du STA301 ki Assignment kar du plzzzzz

[Xpert]

yar dey don ga. Please thora chill man

[frndz]

bhht kar liya chill ab zara kindly solution upload karny ke zehmat kar lyn xpert... ab to extend day bhe mil gya ha kiya wo bhe guzarna ha itna students ka jo apki site par depend karty hain????????????????

[sohail]

O bhai Jaaan, Time is very short.
Ab to solution bhej den.

[sohail]

O paa jee, nai dena ty dus do. k koi nai sta-301 da solution.