CS610 Computer Networks Assignment No. 4 Semester Spring June 2012

[Vuhelper]

Q.1.
How many subnets and hosts per subnet can you get from the network 174.20.0.0/23 Remember for host part at
least 2 bits are required? [10 Marks]
Q.2. Write the class name against each IP address given below, [5Marks]
IP Address Class
122.25.125.10
191.228.30.20
224.25.239.55/8
192.168.88.100/24
222.127.160.79/19

[Vuhelper]

First IP = Class A
2ns IP = Class B
3rd IP = Class D
4th IP = Class C
5th IP = Class C
It is 100% correct

[Vuhelper]

Class A = 1.0.0.0 to 126.0.0.0
Class B = 128.0.0.0 to 191.255.0.0
Class C = 192.0.1.0 to 223.255.255.0

[Vuhelper]

1. How many subnets and hosts per subnet can you get from the network 174.20.0.0/23 Remember for host part at least 2 bits are required? [10 Marks]

The number of hosts from /23 it means that 23 bits are on while others
are off. So take number of bits which are off. For there are 9 bits, which are
off.
2^9 -2 =510 Number of hosts for number of subnets.
Since it class B its default is /16 but according to the question is /23.
So
23-16=7
Hence to get subnets =2^7 =128
Q.2. Write the class name against each IP address given below,



IP Address


Class
122.25.125.10 A
191.228.30.20 B
224.25.239.55/8 D
192.168.88.100/24 C
222.127.160.79/19 C