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STA301 Assignment 3 May 19,2010
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#1
Due date 23:59 20th May, 2010

(Lessons 15-18)


.jpg   1.jpg (Size: 65.82 KB / Downloads: 126)
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#2
Q1 ©
Sample spacing:

{(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)
(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)
(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}

total overcomes are 36
Probability:

1. 3/36 = 1/12
2. 6/36 = 1/6
3. 0/36 = 0
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#3
Qsn #03
solution
total cards= 52
Diamond cards:
A's=1
pictured cards=3(King, queen and jack)
number cards(2 to 10)= 9
Club cards:
A's=1
pictured cards=3(King, queen and jack)
number cards(2 to 10)= 9
spade cards:
A's=1
pictured cards=3(King, queen and jack)
number cards(2 to 10)= 9
heart cards
A's=1
pictured cards=3(King, queen and jack)
number cards(2 to 10)= 9
this was the classification, hope u people get it. now wt does mutually exclusive means" any event in which two outcomes can not occur both at the same time those events are said to b mutually exclusive events"
forexample in tossing a coin head and tail are mutually exclusive events. they cant occur both at the same time.
but in this case we can not say that in drawing a card it is mutually exclusive event that the card will be diamond card and and a king. it can be as a king can be of diamond as well as shown in above classification.
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#4
Thankxxxx Smile
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#5
yar koi 1st question kay part b ka answer bata sakta hai?
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#6
here is the complete solution of STA301 Assignment 3 please download the file




.doc   STA301-Assignment#3-solution.doc (Size: 39 KB / Downloads: 242)
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