Mth101 Assignment No. 1 solution fall 2011 on 19 October, 2011

[saneha]

tel me that is correct


Find equation of the line which is perpendicular to the line

y= 5x+9 and has y-intercept = 6.

I think correct ansewr is

y=5x+9 is darivative w.r.t x

dy/dx=5+0

m=5

then slope of normal is m= -1/5

for normal equation is (y-y1)m =(x-x1)

(y-6)-1/5=(x-0)

-y1/5+6=x

-y+30=5x

y+5x-30=0

this is normal equation

for parpandicular is

y=mx+b

y=-1/5x+6