01-05-2012, 05:21 PM
Suppose that a saleswoman has to visit eight different cities. She must begin her trip in a specific city, but she can visit the other seven cities in any order she wishes. How many possible orders can the saleswoman use when visiting these cities?
Answer.
The number of the possible path between the cities is the number of the permutations of seven elements because the first city is determined but remaining 7 can be ordered arbitrarily. Hence
7!=7*6*5*4*3*2*1=5040
So the possible paths are 5040
Answer.
The number of the possible path between the cities is the number of the permutations of seven elements because the first city is determined but remaining 7 can be ordered arbitrarily. Hence
7!=7*6*5*4*3*2*1=5040
So the possible paths are 5040
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