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Assignment # 1 MTH302 (Spring 2011) New and final April 06
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First question answer
[B]R (interest Rate) = 7/12 = .0058%[/B]



[B]Periods (n) = 17*12= 204[/B]


[B]PMT= 8450[/B]


[B]PV = ?[/B]


[B]= PMT * [((1 + r)^n – 1) / (r * (1 + r)^n][/B]


[B]=8450*(((1+0.0058)^204-1)/(0.0058*(1+0.0058)^204)) =1009126

Question 3 answer
[/B]If 3 students are absent out of a class of 24, what percent of the students are absent?
[B]Total = 24[/B]



[B]Absent = 3[/B]


[B]Percent absent = (3/27)*100 = 11.11%[/B]


[B](b) If 12.5% of the students are absent in a class of 24, how many students are absent?[/B]


[B]12.5% means out of 100 12.5 students are absent[/B]


[B]= (12.5/100)*24 = 3 students are absent[/B]


[B]© If 3 students are absent and these comprise 12.5% of the class, how many students are enrolled in the class?[/B]



[B]If 12.5 students are absent then total students = 100[/B]


[B]If 1 student is absent then total students = 100/12.5[/B]


[B]If 3 students are absent total students = (100/12.5)*3 = 24[/B]


[B]Question 4:[/B]


[B]What principal does Ali need to invest at 25% p.a.(per annum) compounding monthly so that he ends up with Rs. 100,000 at the end of five years? Also find compound interest.[/B]


Interest rate is 25% per annum, and compounded monthly, then the value of 'i' to use in the formula is 25%/12 = 2.08% = .0208
i = .0208
A = 100,000




n = 5 years = 5*12 = 60 months


( As interest is compounded after every month ,we need to get all periods by multiplying years * months )
P = ?
P= A/(1+i)^n



P= 100,000/((1+.0208)^60) = 29077.71


[B]Question 4:[/B]


[B]What principal does Ali need to invest at 25% p.a.(per annum) compounding monthly so that he ends up with Rs. 100,000 at the end of five years? Also find compound interest.[/B]


Interest rate is 25% per annum, and compounded monthly, then the value of 'i' to use in the formula is 25%/12 = 2.08% = .0208
i = .0208
A = 100,000




n = 5 years = 5*12 = 60 months


( As interest is compounded after every month ,we need to get all periods by multiplying years * months )
P = ?
P= A/(1+i)^n



P= 100,000/((1+.0208)^60) = 29077.71



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Assignment # 1 MTH302 (Spring 2011) New and final April 06 - by Xpert - 04-13-2011, 02:46 AM

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